How to calculate the derivative of a function? Explained with calculations
In this era of
technology and development, the applications and courses are also increasing
day by day. One of the main and frequently used subjects is mathematics.
Mathematics is a subject that deals with numerical and complex problems of
various kinds.
There are different branches of mathematics such as geometry, algebra, trigonometry, calculus, etc. Calculus is further divided into two types one is differential and the other is integral. In this article, we will learn the basics of the differential along with its examples and solutions.
What is differential calculus?
Differential
calculus is one of the main types of calculus that is used to evaluate the
slope (steepness) of the tangent line. It is generally used to evaluate the
rate of change of a function with respect to its corresponding variable.
It is also known
as differentiation, the process of finding the derivative of the function with
respect to its independent variable. It is denoted by f’(z) or d/dz. The
differential of the function is evaluated easily with the help of rules of
differentiation.
One of the best and most commonly used techniques
for finding the derivative of the function is to get help from limit
calculus as it can define the differential of the function with the help of the
first principle method.
First principle method equation
The equation
used to calculate the differential of the function with the help of limit
calculus is given below.
d/dz [f(z)] =
limh→0 f(z + h) – f(z) / h
·
d/dz = notation of differential
·
lim = notation of limit
·
h = specific point
·
f(z) = given function
·
z = corresponding variable
·
f(h + z) = function increased by h
Rules of differential calculus
Here are the
basics and well-known rules of differentiation used to evaluate the derivative
of the function.
Rules name |
Rules |
Trigonometry Rule |
d/dz [sin(z)] = cos(z) |
Power Rule |
d/dz [f(z)]n = n [f(z)]n-1
* [f’(z)] |
Quotient Rule |
d/dz [f(z) / g(z)] = 1/[g(z)]2 [g(z)
* [f’(z)] - f(z) * [g’(z)]] |
Product Rule |
d/dz [f(z) * g(z)] = g(z) * [f’(z)] + f(z) *
[g’(z)] |
Constant Rule |
d/dz [L] = 0, where L is any constant |
Difference Rule |
d/dz [f(z) - g(z)] = [f’(z)] - [g’(z)] |
Sum Rule |
d/dz [f(z) + g(z)] = [f’(z)] +
[g’(z)] |
Exponential Rule |
d/dz [ez] = ez |
Constant function Rule |
d/dz [L * f(z)] = L [f’(z)] |
How to calculate the derivative
of a function?
To evaluate the
derivative of the function, you can use rules of differentiation or the first
principle method. These techniques will help you to solve the problems of
derivatives manually. A derivative calculator
with steps can be used to evaluate the derivative online without involving
the larger calculations.
Here are a few
examples of differentiation to learn how to calculate the derivative of the
function.
Example 1: By
the first principle method
Calculate the
derivative of the given function with respect to “z”.
f(z) = 3z2
– 12z + 4
Solution
Step 1:
First of all, write the general expression of the first
principle method that is helpful in calculating the derivative of the function.
d/dz [f(z)] = limh→0 f(z + h) – f(r) / h
Step 2: Now take the given
function f(z) and make f(z + h) that is required in the above expression.
f(z) = 3z2
– 12z + 4
f(z + h) = 3(z +
h)2 – 12(z + h) + 4
f(z + h) = 3(z2
+ 2hz + h2) – 12(z + h) + 4
f(z + h) = 3z2
+ 6hz + 3h2 – 12z – 12h + 4
Step 3: Now substitute the
values in the general expression of the first principle method
d/dz [3z2
– 12z + 4] = limh→0 [3z2 + 6hz + 3h2 – 12z – 12h + 4] – [3z2
– 12z + 4] / h
d/dz [3z2
– 12z + 4] = limh→0 [3z2 + 6hz + 3h2 – 12z – 12h + 4 – 3z2
+ 12z – 4] / h
d/dz [3z2
– 12z + 4] = limh→0 [3z2 + 6hz + 3h2 – 12z – 12h +
4 – 3z2 + 12z – 4] / h
d/dz [3z2
– 12z + 4] = limh→0 [6hz + 3h2 – 12h] / h
d/dz [3z2
– 12z + 4] = limh→0 [6hz/h + 3h2/h – 12h/h]
d/dz [3z2
– 12z + 4] = limh→0 [6z + 3h – 12]
d/dz [3z2
– 12z + 4] = limh→0 [6z] + limh→0 [3h] – limh→0 [12]
d/dz [3z2
– 12z + 4] = 6z + [3(0)] – 12
d/dz [3z2
– 12z + 4] = 6z – 12
Example 2: By
using the laws
Calculate the
derivative of the given function with respect to “y”.
f(y) = 3y3
+ 5y4 – 2y * 6y3 – 7y
Solution
Step 1:
First of all, write the given function f(y) and the corresponding
variable and apply the notation of differentiation to it.
f(y) = 3y3
+ 5y4 – 2y * 6y3 – 7y
corresponding
variable = y
d/dy f(y) = d/dy
[3y3 + 5y4 – 2y * 6y3 – 7y]
Step 2:
Now apply the notation of differentiation to each term
of the function with the help of sum and difference rules of differential
calculus.
d/dy [3y3
+ 5y4 – 2y * 6y3 – 7y] = d/dy [3y3] + d/dy [5y4]
– d/dy [2y * 6y3] – d/dy [7y]
Step 3: Now apply the product
rule of differential calculus.
d/dy [3y3
+ 5y4 – 2y * 6y3 – 7y] = d/dy [3y3] + d/dy [5y4]
– [6y3 d/dy [2y] + 3y d/dy [6y3]] – d/dy [7y]
d/dy [3y3
+ 5y4 – 2y * 6y3 – 7y] = d/dy [3y3] + d/dy [5y4]
– 6y3 d/dy [2y] – 3y d/dy [6y3] – d/dy [7y]
Step 3:
Now take the constant coefficients outside the
differential notation.
d/dy [3y3
+ 5y4 – 2y * 6y3 – 7y] = 3d/dy [y3] + 5d/dy [y4]
– 12y3 d/dy [y] – 18y d/dy [y3] – 7d/dy [y]
Step 4:
Now differentiate the above expression with the help of
the power rule.
d/dy [3y3
+ 5y4 – 2y * 6y3 – 7y] = 3 [3 y3-1] + 5 [4 y4-1]
– 12y3 [y1-1] – 18y [3 y3-1] – 7 [y1-1]
d/dy [3y3
+ 5y4 – 2y * 6y3 – 7y] = 3 [3 y2] + 5 [4 y3]
– 12y3 [y0] – 18y [3 y2] – 7 [y0]
d/dy [3y3
+ 5y4 – 2y * 6y3 – 7y] = 3 [3 y2] + 5 [4 y3]
– 12y3 [1] – 18y [3 y2] – 7 [1]
d/dy [3y3
+ 5y4 – 2y * 6y3 – 7y] = 9y2 + 20y3
– 12y3 – 54y3 – 7
d/dy [3y3
+ 5y4 – 2y * 6y3 – 7y] = 9y2 + 8y3
– 54y3 – 7
d/dy [3y3
+ 5y4 – 2y * 6y3 – 7y] = 9y2 – 46y3
– 7
Final words
Now you can grab
all the basics of calculating the derivative of the function from this post. As
we have discussed all the basics of differential calculus along with its
definition and solved examples. Now you can be a master in this topic by just grabbing
the basics of this post.
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